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6a^2+2a-2.5=0
a = 6; b = 2; c = -2.5;
Δ = b2-4ac
Δ = 22-4·6·(-2.5)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-8}{2*6}=\frac{-10}{12} =-5/6 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+8}{2*6}=\frac{6}{12} =1/2 $
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